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#1
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reagrding closing the output window console of vizard
Hi jeff,
I have 4 Scripts with theie different vizconnects, I m calling a script using a subprocess module -subprocess("script.py",shell=True) The 1st script executed on an event from wand executes a second script,but the 1st script is not closed,and so on. I want when i start or executes a new script,which terminated the previous console output window. The are four scripts.. launch 1st script... call secnd script from 1st script-2nd oupt console opened ,the first output console should get closed and the same for 2nd,3rd and 4th . I have tried: sys.exit(),os.exit() and others : for ex: 1st script: import os import vizinfo import sys import viz import subprocess viz.setMultiSample(4) viz.fov(60) viz.go() piaz=viz.add('dojo.osgb') #subprocess.call("pyOne.py", shell=True) def changeExit(ce): print 'change two exit' subprocess.call("pyTwo.py", shell=True) if __name__ == '__main__':later( ) def later( ): import sys print 'Bye sys world' sys.exit(42) print 'Never reached' #if __name__ == '__main__': #subprocess.call("pyTwo.py", shell=True) #later( ) viz.callback(viz.KEYDOWN_EVENT, changeExit) #---------------------new 2nd script------------ 2nd script: import viz import vizshape import vizact import os import vizinfo import sys import subprocess viz.setMultiSample(4) viz.fov(60) viz.go() piaz=viz.add('dojo.osgb') def changeExitTwo(): print 'Exitted the pyOne' sys.exit('pyTwo Died') #os._exit(0) #raise SystemExit def changeTwo(word): print 'I m in pyTwo to exit pYone and call pyThree' subprocess.call("pyThree.py", shell=True) import pyOne as p p.changeExit() #vizact.ontimer(1,changeExitTwo) viz.callback(viz.KEYDOWN_EVENT, changeTwo) if __name__ == '__main__': print 'Rajnish Vishwakarma' Pls suggest me |
#2
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Regarding sript swith and close the previous script
Hi jeff,
I have 4 Scripts with theie different vizconnects, I m calling a script using a subprocess module -subprocess("script.py",shell=True) The 1st script executed on an event from wand executes a second script,but the 1st script is not closed,and so on. I want when i start or executes a new script,which terminated the previous console output window. The are four scripts.. launch 1st script... call secnd script from 1st script-2nd oupt console opened ,the first output console should get closed and the same for 2nd,3rd and 4th . I have tried: sys.exit(),os.exit() and others : I m testing on the keyboard event(same can be applied to wand event0 for ex: 1st script: import os import vizinfo import sys import viz import subprocess viz.setMultiSample(4) viz.fov(60) viz.go() piaz=viz.add('dojo.osgb') #subprocess.call("pyOne.py", shell=True) def changeExitTwo(ce): print 'change two exit' subprocess.call("pyTwo.py", shell=True) if __name__ == '__main__':later( ) def later( ): import sys print 'Bye sys world' sys.exit(42) print 'Never reached' #if __name__ == '__main__': #subprocess.call("pyTwo.py", shell=True) #later( ) viz.callback(viz.KEYDOWN_EVENT, changeExitTwo) #------------------------2nd Script------------------------ 2nd script import viz import vizshape import vizact import os import vizinfo import sys import subprocess viz.setMultiSample(4) viz.fov(60) viz.go() piaz=viz.add('gallery.osgb') def changeTwo(word): print 'I m in pyTwo to exit pYone and call pyThree' subprocess.call("pyThree.py", shell=True) ##Rest of code to call third script here and exit the second one viz.callback(viz.KEYDOWN_EVENT, changeTwo) if __name__ == '__main__': print 'Rajnish Vishwakarma' Pls ignore my last post. Pls assit me for the following. |
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