Regarding sript swith and close the previous script
Hi jeff,
I have 4 Scripts with theie different vizconnects,
I m calling a script using a subprocess module -subprocess("script.py",shell=True)
The 1st script executed on an event from wand executes a second script,but the 1st script is not closed,and so on.
I want when i start or executes a new script,which terminated the previous console output window.
The are four scripts..
launch 1st script...
call secnd script from 1st script-2nd oupt console opened ,the first output console should get closed and the same for 2nd,3rd and 4th .
I have tried:
sys.exit(),os.exit() and others :
I m testing on the keyboard event(same can be applied to wand event0
for ex:
1st script:
import os
import vizinfo
import sys
import viz
import subprocess
viz.setMultiSample(4)
viz.fov(60)
viz.go()
piaz=viz.add('dojo.osgb')
#subprocess.call("pyOne.py", shell=True)
def changeExitTwo(ce):
print 'change two exit'
subprocess.call("pyTwo.py", shell=True)
if __name__ == '__main__':later( )
def later( ):
import sys
print 'Bye sys world'
sys.exit(42)
print 'Never reached'
#if __name__ == '__main__':
#subprocess.call("pyTwo.py", shell=True)
#later( )
viz.callback(viz.KEYDOWN_EVENT, changeExitTwo)
#------------------------2nd Script------------------------
2nd script
import viz
import vizshape
import vizact
import os
import vizinfo
import sys
import subprocess
viz.setMultiSample(4)
viz.fov(60)
viz.go()
piaz=viz.add('gallery.osgb')
def changeTwo(word):
print 'I m in pyTwo to exit pYone and call pyThree'
subprocess.call("pyThree.py", shell=True)
##Rest of code to call third script here and exit the second one
viz.callback(viz.KEYDOWN_EVENT, changeTwo)
if __name__ == '__main__':
print 'Rajnish Vishwakarma'
Pls ignore my last post.
Pls assit me for the following.
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